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∫sin2x.logcosxdx is equal to (A) cos^2x(1/2 + logcosx) + k

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∫sin2x.logcosxdx is equal to

(A) cos2x(1/2 + logcosx) + k

(B) cos2xlogcosx + k

(C) cos2x(1/2 - logcosx) + k

(D) None of these 

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Answer is (C) cos2x(1/2 - logcosx) + k

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