Answer is (A), (B), (C)
See Fig.
If P be (x, y, z) then from the figure, x = r sinθ cosϕ, y = r sinθ sinϕ, z = r cosθ
⇒ 1 = r sinθ cosϕ, 2 = r sinθ sinϕ, 3 = r cosθ
⇒ 12 + 22 + 32 = r2 ⇒ r = ± √14
Therefore,
sinθ cosϕ = 1/√14 sinθsinϕ = 2/√14, cosϕ = 3/√14
(neglecting negative sign as q and f are acute)
Therefore,