Correct option (A) - 2/n
Let a be the first term and d be the common difference of the given AP. Then as given the (m + 1)th, (n + 1)th and (r + 1)th terms are in GP. So,a + md,a + nd,a + rd are in GP. This gives
(a + md)2 = (a + md)(a + rd)
⇒ d/a = 2n - (m + r) = d(mr - n2)
⇒ d/a = 2n - (m + r)/mr - n2 .............(1)
Next, m,n,r in HP. So
n = 2mr/m + r ...............(2)
From Eqs. (1) and (2)
