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in Physics by (33.0k points)

A stone is thrown vertically upwards with an initial velocity of 19.6 m-1. After how long will the stone strike the ground? Take g = 9.8 ms-2.

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Initial velocity u = +19.6 ms-1. The stone after reaching the highest point comes back to the initial point

∴ The displacement = 0.

a = g = – 9.8 ms-2

Let t be the time taken to reach the ground

From s = ut + 1/2at2, we have

0 = 19.6t – 1/2 × 9.8 × t2

4.9t– 19.6t = 0

Dividing throughout by 4.9t, we have t = 4s. Hence, the stone reaches the ground after 4s.

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