f(x) = x^3 + 4x^2 – 3x + 10, g(x) = x + 4

Question

Using the remainder theorem, find the remainder when f(x) is divided by g(x) and verify the by actual division :

f(x) = x³ + 4x² – 3x + 10, g(x) = x + 4

Comments

Ekdam sahi answer

Answer 1

f(x) = x³ + 4x² – 3x + 10, g(x) = x + 4 

Put g(x) = 0 

⇒ x + 4 = 0 or x = -4 

Remainder = f(-4) 

Now, 

f(-4) = (-4)³ + 4(-4)² – 3(-4) + 10 

= -64 + 64 + 12 + 10 

= 22

Actual Division: