The given pair of equations are:
3x – (y + 7)/11 + 2 = 10…………(i)
2y + (x + 11)/7 = 10…………….(ii)
From equation (i)
33x – y – 7 + 22 = (10 x 11) [After taking LCM]
⇒ 33x – y + 15 = 110
⇒ 33x + 15 – 110 = y
⇒ y = 33x – 95………. (iv)
From equation (ii)
14 + x + 11 = (10 x 7) [After taking LCM]
⇒ 14y + x + 11 = 70
⇒ 14y + x = 70 – 11
⇒ 14y + x = 59 …………(iii)
Substituting (iv) in (iii) we get,
14 (33x – 95) + x = 59
⇒ 462x – 1330 + x = 59
⇒ 463x = 1389
⇒ x = 3
Putting x = 3 in (iii) we get,
⇒ y = 33(3) – 95
∴ y= 4
The solution for the given pair of equations is x = 3 and y = 4 respectively.
