Question

Find the probability of throwing at most 2 sixes in 6 throws of a single die.

Answer 1

When a die is thrown, 

Probability of getting a six = \(\frac{1}{6}\)

Probability of not getting a six = 1 - \(\frac{1}{6}\) = \(\frac{5}{6}\) 

Probability of getting at most 2 sixes in 6 throws of a single die = P (0) + P (1) + P (2)