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in Linear Equations by (56.3k points)

The present age of father is 3 years more than three times of the age of the son. Three years hence, father’s age will be 10 years more than twice the age of the son. Determine their present age.

1 Answer

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Best answer

Let’s assume the present ages of the father as x years and that of his son’s age as y years.

From the question it’s given that, 

The present age of father is three years more than three times the age of the son. 

So, the equation formed is 

x = 3y + 3 

x – 3y - 3 = 0 …….. (i) 

Also again from the question it’s given as, 

After 3 years, father’s age will be (x + 3) years and son’s age will be (y + 3) years. 

Furthermore, the relation between their ages after 3 years is given below 

x + 3 = 2(y + 3) + 10 

x – 2y – 13 = 0 …….. (ii)

Thus, by solving (i) and (ii), we get the required solution

Using cross-multiplication, we have

⇒x = 33, y = 10 

Hence, The present age of father = 33 years and the present age of his son = 10 years.

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