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If an electromagnetic wave propagating through vacuum is described by,

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If an electromagnetic wave propagating through vacuum is described by,
E = E0 sin (Kx – wt); B = B0 sin (Kx -ωt) then,
(A) E0K = B0ω
(B) E0B0 = ωK
(C) E0ω = B0K
(D) E0B0 = ω/K

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The answer is (A) E0K = B0ω

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