Question

Determine the nature of the roots of the quadratic equation:

3x² – 4√3x + 4 = 0

Answer 1

Here, a= 3, b= – 4√3, c= 4

D = (- 4√3)² -4(3)(4)

= 48 – 48

= 0

It’s seen that D = 0 and hence, the given equation has only 1 real and equal root.