LIVE Course for free

Rated by 1 million+ students
Get app now
0 votes
11.7k views
in Physics by (60.1k points)

A conducting wire of length I, lying normal to a magnetic field B, moves with a velocity v as shown in figure (34-E11). (a) Find the average magnetic force on a free electron of the wire, (b) Due to this magnetic force, electrons concentrate at one end resulting in an electric field inside the wire. The redistribution stops when the electric force on the free electrons balances the magnetic force. Find the electric field developed inside the wire when the redistribution stops, (c) What potential difference is developed between the ends of the wire?

1 Answer

0 votes
by (148k points)
selected by
 
Best answer

(a) Velocity of electron = υ

Magnetic force on electron

F = eυB

(b) F = qE; F = eυB

or, qE = eυB

=> eE = eυB or, vector E= υB

(c) E = dV/dr  = V/I

=> V = lE = lυB

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...