Given,
AC = 24 cm and BC = 10 cm
Since, AB is the diameter of the circle
Angle ACB = 90o
So, using Pythagoras theorem
AB2 = AC2 + BC2
= 242 + 102
= 576 + 100
= 676
AB = √676 = 26 cm
Thus, the radius of the circle = 26/2
= 13 cm
The area of shaded region = Area of semi-circle – Area of triangle ACB
= 1/2 πr2 – 1/2 x b x h
= 1/2 (22/7)132 – 1/2 x 10 x 24
= 265.33 – 120
= 145.33 cm2