
Given,
Height of the circular Cylinder (h1) = 12 cm
Base radius of the circular Cylinder (r) = 5 cm
Height of the conical hole = Height of the circular cylinder, i.e., h1 = h2 = 12 cm
And, Base radius of the conical hole = Base radius of the circular Cylinder = 5 cm
Let’s consider, L as the slant height of the conical hole.
Then, we know that

Now,
The total surface area of the remaining portion in the circular cylinder (V1) = πr2 + 2πrh + πrl
V1 = π(5)2 + 2π(5)(12) + π(5)(13)
V1 = 210 π cm2
And, the volume of the remaining portion of the circular cylinder = Volume of the cylinder – Volume of the conical hole
V = πr2h – 1/3 × 22/7 × r2 × h
V = π(5)2(12) – 1/3 × 22/7 × 52 × 12
V = 200 π cm2