
Given,
Diameter of the cylinder = 20 m
So, its radius of the cylinder (R) = 10 m
Height of the cylinder (h1) = 2.5 m
Radius of the cone = Radius of the cylinder (r) = 15 m
Height of the Cone (h2) = 7.5 m
Let us consider L as the slant height of the Cone, then we know that
L2 = r2 + h22
L2 = 152 + 7.52
L2 = 225 + 56.25
L2 = 281.25
L = 12.5 m
Now,
Volume of the cylinder = πR2h1 = V1
V1 = π(10)2 2.5
V1 = 250 πm3
Volume of the Cone = 1/3 × 22/7 × r2 × h22 = V2
V2 = 1/3 × 22/7 × 102 × 7.5
V2 = 250π m3
So, the total capacity of the tent = volume of the cylinder + volume of the cone = V1 + V2
V = 250 π + 250 π
V = 500π m3
Hence, the total capacity of the tent is 500π m3
And, the total area of canvas required for the tent is S = 2 πRh1 + πrL
S = 2(π)(10)(2.5) + π(10)(12.5)
S = 550 m2
Therefore, the total cost for canvas is (100) (550) = Rs. 55000