Given,
Diameter of the hemisphere = 2 m
So, the radius of the hemisphere (r) = 1 m
Height of the cylinder (h1) = 2 m
And, the volume of the Cylinder = πr2h1 = V1
V1 = π(1)22
V1 = 22/7 × 2 = 44/7 m3
As at each of the ends of the cylinder, hemispheres are attached.
So, totally there are 2 hemispheres.
Then the volume of two hemispheres = 2 × 2/3 × 22/7 × r3 = V2
V2 = 2 × 2/3 × 22/7 × 13
V2 = 22/7 × 4/3 = 88/21 m3
Thus,
The volume of the boiler (V) = volume of the cylindrical portion + volume of the two hemispheres
V = V1 + V2
V = 44/7 + 88/21
V = 220/21 m3
Therefore, the volume of the boiler 220/21 m3.