Given,
A milk container of the form of frustum of a cone
The radius of the lower end (r1) = 8 cm
The radius of the upper end (r2) = 20 cm
Let h be its height, h = 16 cm
Then, the capacity of the container = Volume of frustum of the cone
= 1/3 π(r22 + r12 + r1 r2 )h
= 1/3 π(202 + 82 + (20) (8) ) x 16
= 10459.42 cm3
= 10.46 litres
Now, given that cost of 1 litre of milk = Rs 44
Then the cost of 10.46 litres of milk = Rs (44 x 10.46) = Rs 460.24