Given: (2 + √3) is one of zero of polynomial x2 ‒ 4x + 1.
To find: Other zero
Since given polynomial is a quadratic so it has only two zeros.
Let other zero be x.
Now,
Sum of zeros = -(coefficient of x)/(coefficient of x^2)
x + (2 + √3) = -(-4/1) = 4
x + 2 + √3 = 4
or x = 2 – √3
Hence, the other zero is (2 -√3).