Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
8.7k views
in Probability and Probability Distribution by (48.0k points)

Let X be random variable which assumes value x1, x2, x3, x4 such that 2P(X = x1) = 3P(X = x2) = 4P(X = x3) = 5P(X = x4) find the probability distribution of X.

1 Answer

+1 vote
by (46.3k points)
selected by
 
Best answer

Given 2P(X = x1) = 3p(x = x2) = P(X = x3

= 5 P(X = x4) = K

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...