Question

A man looks from the top of tower that the angle of depression of a point of the earth is 60°. If the distance of the point is 25 m from the base of the tower, them find out the height of the tower.

Answer 1

AB is a tower. The angle of depression of top of tower from point A to point C is 60°.

So ∠XAC = 60°

⇒ ∠ACB = 60°

From right angled ΔABC,

tan 60° = AB/BC

√3 = AB/25

Hence, height of tower = 25√3 m