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in Sets, Relations and Functions by (51.6k points)
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Let S be the set of all real numbers and let

R = {(a, b): a, b ∈ S and a = ± b}.

Show that R is an equivalence relation on S.

1 Answer

+1 vote
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Best answer

We know that a = ± b and a2 = b2 are equal

It is given that {(a, b): a, b ∈ S and a2 = b2}

Here, (a, a) ∈ R and a2 = a2 is true.

Hence, R is reflexive where (a, b) ∈ R

We know that a2 = b2 and b2 = a2 where (b, a) ∈ R

Hence, R is symmetric.

If (a, b) ∈ R and (b, c) ∈ R

We know that a2 = b2 and b2 = c2 we get a2 = c2 where (a, c) ∈ R

Hence, R is transitive.

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