Question

A rod of length L and mass M is pulled by a force F₁ at its one end. Find tension at a distance y from the end where F₁ acts. 

(A) F₁(1 -y/L) 

(B) F₁(y/L) 

(C) F₁(1 + y/L) 

(D) None of these

Answer 1

(A) F₁(1 -y/L) 

Explanation:

acceleration of string =F/M, 

mass of portion of string between distance y and other end of string=M(1-y/L). 

tension at distance y=M(1-y/L)F/M

=F(1-y/L)