(B) 10/3kgwt
Forces acting at 1 kg load, 5 kg load and pulley are shown in figure. Let us assume 1 kg load moves upward with acceleration a and 5 kg load moves downward with acceleration a. Let T be the tension in the string. at 1 kg load :-
T - g = a ..................(1)
at 5 kg load :- T - 5g = -5a ...............(2)
By solving the above two equations, we get a = (2/3)g and T = (5/3)g
Hence tension in the spring, 2T = (10/3)kgwt