Given: ABCD is a trapezium in which AB || DC and E is mid-point of AD.
Construction: Draw EF || AB and join A to C.
To prove: F is mid-point of BC.
Proof: In ∆ADC, E is mid-point of AD and EO is drawn parallel to AB i.e., parallel to DC also.
Then by using converse of mid- point theorem, O will be the mid-point of AC.
Similarly, in ∆ABC, O is the mid-point of AC and OF || AB.
⇒ F will be the mid-point of BC.
(by converse of mid-point theorem)