Given: O is the centre of circle, chord PQ = chord RS
To prove: arc PMQ = arc RNS

Proof:
In ∆POQ and ∆ROS,
[side PO ≅ side RO side OQ ≅ side OS]
[Radii of the same circle]
chord PQ ≅ chord RS [Given]
∴ ∆POQ ≅ ∆ROS [SSS test of congruency]
∴ ∠POQ ≅ ∠ROS (i) [c.a.c.t.]
m(arc PMQ) = ∠POQ (ii)
m(arc RNS) = ∠ROS (iii) [Definition of measure of minor arc]
∴ arc PMQ ≅ arc RNS [From (i), (ii) and (iii)]