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Why does the following reaction occur? 

XeO64-(aq) + 2F(aq) + 6H+(aq) → XeO3(g) + F2(g) + 3H2O(l) 

What conclusion about the compound Na4XeO6 (of which XeO64- is a part) can be drawn from the reaction.

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1 Answer

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The given reaction occurs because  XeO64- oxidises F- and F-

 

reduces  XeO64-  In this reaction, the oxidation number (O.N.) of Xe decreases from +8 in XeO64- to +6 in XeO3 and the O.N. of F increases from –1 in F to O in F2

Hence, we can conclude that Na4XeO6 is a stronger oxidising agent than F .

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