True
Let P (5, - 3) be the point which divides the line segment joining the points A (7, - 2) and B (1, - 5) in the ratio k:1 internally.
By using the section formula,
The coordinate of point P
⇒ k + 7 = 5k + 5
⇒ - 4k = - 2
∴ k = 1/2
So the point P divides the line segment AB in ratio 1:2
Hence, Point P in the point of trisection of AB.