Let us consider two G.P’s
a, ar, ar2, ar3, …, arn-1
and a1, a1r1, a1r12, …, a1r1n–1
Now, we will find the sum of these two G.Ps, we get
(a + a1) + (ar + a1r1) + (ar2 + a1r12) + … + (arn-1 + a1r1n-1)

So, the sum of two G.Ps is not a G.P because the common ratio is not same.
Now, we will find the difference of the two G.Ps
(a – a1) + (ar – a1r1) + (ar2 – a1r12) + … + (arn-1 – a1r1n-1)

So, the difference of two G.Ps is not a G.P because the common ratio is not same.
Hence, the given statement is FALSE