Let fixed hostel charge (monthly) = Rs x
and cost of food for one day = Rs y
In case of student A,
x + 25y = 1750 …(i)
In case of student B,
x + 28y = 1900 …(ii)
On subtracting Eq. (i) from Eq. (ii), we get
x + 28y – x – 25y = 1900 – 1750
⇒ 3y = 150
⇒ y = 50
On putting the value of y = 50 in Eq. (i), we get
x + 25(50) = 1750
⇒ x + 1250 = 1750
⇒ x = 1750 – 1250 = 500
Hence, monthly fixed charges is Rs. 500 and cost of food per day is Rs. 50