Question

Give the relationship between the wavelength of light and its angle of deviation, when it is passed through a prism.

Answer 1

Let,

A = angle of prism

D= angle of deviation

N = refractive index

λ_vacuum = wavelength in vacuum

λ_medium = wavelength in medium

We know

n = \(\frac{sin(\frac{A\,+\,D}{2})}{sin(\frac{A}{2})}\)

n = λ_vacuum /λ_medium 

so, 

λ_medium/λ_vacuum x \(\frac{sin(\frac{A}{2})}{{sin(\frac{A\,+\,D}{2})}{}}\)