Question

A right pyramid is on a regular hexagonal base. Each side of the base is 10 m and its height is 30 m. Find the volume of the pyramid ?

Answer 1

Volume of a pyramid = \(\frac{1}{3}\) × (Area of the base) × Height

= \(\frac{1}{3} \times \frac{3\sqrt{3}}{2} \times (5)^2 \times 30 \)  = 649.52 m³ ≈ 650m³  

(Area of a regular hexagon of side 'a' = \(\frac{3\sqrt{3}}{2} a^2\) )