
Let P and Q be the points of trisection of AB, i.e. AP = PQ = QB
∴ P divides AB internally in the ratio 1: 2.
∴ the coordinates of P, by applying the section formula, are

Here, m1 = 1, m2 = 2
(x1, y1) = (2, 3) and (x2, y2) = (6, 5)
Putting the above values in the above formula, we get

Now, Q also divides AB internally in the ratio 2: 1. So, the coordinates of Q are

Here, m1 = 2, m2 = 1
(x1, y1) = (2, 3) and (x2, y2) = (6, 5)
Putting the above values in the above formula, we get

Therefore, the coordinates of the points of trisection of the line segment joining A and B are (10/3, 11/3) and (14/3, 13/3).