# Let m be the mid point and b be the upper limit of a class in a continuous frequency distribution. The lower limit of the class is (1) 2m – b

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Let m be the mid point and b be the upper limit of a class in a continuous frequency distribution. The lower limit of the class is

(1) 2m – b

(2) 2m + b

(3) m – b

(4) m – 2b

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Answer is (1) 2m – b