(c) 1 hr. 15 min
Speed of the boatman upstream = \(\frac21\) km/hr = 2 km/hr
Speed of the boatman downstream = \(\frac{1}{\frac{10}{60}}\) km/hr = 6 km/hr
∴ Speed of boatman in stationary water = \(\frac12(6+2)\) km/hr = 4 km/hr
∴ Time taken to cover 5 km in stationary water = \(\frac54\) hrs = \(1\frac14\) hrs = 1 hr. 15 min.