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If \(a=\frac{x}{x+y} \,\text{and}\,b=\frac{y}{x-y}\,\text{then}\,\frac{ab}{a+b}\) is equal to

(a) \(\frac{xy}{x^2+y^2}\)

(b) \(\frac{x^2+y^2}{xy}\)

(c) \(\frac{x}{x+y}\)

(d) \(\big(\frac{y}{x+y}\big)^2\)

1 Answer

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Best answer

(a) \(\frac{xy}{x^2+y^2}\)

ab = \(\big(\frac{x}{x+y}\big) \times\big(\frac{y}{x-y}\big)\)

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