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In a process, 701 J of heat is absorbed by a system and 394 J work is done by the system. What is the change in internal energy for the process?

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Given, q = 701 J

W = − 394 J

(As work is done by the system)

\(\Delta\)U = ?

According to first law of thermodynamics,

\(\Delta\)U = q + W

= 701 + (−394)

= 701 − 394 = 307 J

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