Sarthaks Test
0 votes
5 views
in Linear Equations by (34.6k points)
closed by

Solve the following equations and also check your result in each case:

\(\frac{(3x+1)}{16}+\frac{(2x-3)}7=\frac{(x+3)}8+\frac{(3x-1)}{14}\)

1 Answer

+1 vote
by (35.1k points)
selected by
 
Best answer

 \(\frac{(3x+1)}{16}+\frac{(2x-3)}7=\frac{(x+3)}8+\frac{(3x-1)}{14}\)

On transposing \(\frac{x+3}8+\frac{3x-1}{14}\) to LHS, we get

\(\frac88+\frac{14}{14}\) = 2

We got LHS=RHS

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...