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Find the multiplicative inverse of

(i) \(\frac{-3}{4}\)

(ii) \(\frac{11}{4}.\)

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Multiplicative inverse of a rational number \(\frac{a}{b}\) = \(\frac{b}{a}\)

Therefore,

(i) Negative inverse of \(\frac{-3}{4}\) = \(\frac{4}{-3}\) 

\(\frac{4}{-3}=\frac{4\times-1}{-3\times-1}=\frac{-4}{3}\)

(ii) Negative inverse of \(\frac{11}{4}\) = \(\frac{4}{11}\)

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