Correct option is a 3.5 cm
Given,
Volume of 1st cube = \(\cfrac{1}8cm^3\)
Volume of second cube = 1 cm3
Volume of third cube = 8 cm3
∴edge of first cube = a1 =\(\sqrt[3]{\cfrac18}\) = \(\cfrac12\) cm
∴ edge of second cube = a2 = \(\sqrt[3]1\) = 1 cm
∴ edge of third cube = a3 = \(\sqrt[3]8\) = 2 cm
Hence height of cubes together = a1 + a2 + a3 = \(\cfrac12\) + 1 + 2
= \(\cfrac72\) = 3.5 cm