Sarthaks Test
0 votes
in Mathematics by (35.6k points)

In the given below fig, rays OA, OB, OC, OP and OE have the common end point O. Show that ∠AOB + ∠BOC + ∠COD + ∠DOE + ∠EOA = 360°.

1 Answer

+1 vote
by (61.7k points)
selected by
Best answer

Given that 

Rays OA, OB, OD and OE have the common end point O. 

A ray of opposite to OA is drawn

By adding (1) and (2) equations we get 

∠AOB + ∠BOC + ∠COF + ∠AOE + ∠DOF + ∠DOE = 360o 

∠AOB + ∠BOC + ∠COD + ∠DOE + ∠EOA =360o 

Hence proved

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.