1. Oxidising agent – Ag
Reducing Agent – Cu
2. Assigning oxidation number:

Calculate the increase and decrease in the oxidation number and make them equal:
Cr2O72- + Fe2+ → Cr3+ + Fe3+
Equating the ionic charges:
Cr2O72- + 6Fe2+ +14H+ → 2Cr3+ + 6Fe3+
Balancing H and O :
Cr2O72- + 6Fe2+ +14H+ → 2Cr3+ + 6Fe3+ + 7H2O