(i) यहाँ
`0.46 xx 0.46 - 0.36 xx 0.36`
माना `a = 0.46, b = 0.36`
`therefore" "a xx a - b xx b`
`a^(2)-b^(2) = (a-b)(a+b)`
`therefore" "(0.46)^(2)-(0.36)^(2)=(0.46-0.36)(0.46+0.36)=(0.10)(0.82)=0.082`
(ii) यहाँ `105 xx 106 = (100 + 5)(100+6)`
दिया गया व्यंजक (x + a) (x + b) के रूप का है । क्योकि,
`(x+a)(x+b)=x^(2)+(a+b)x + ab`
`therefore" "(100 + 5)(100+6)=(100)^(2)+(5+6)100 + 5 xx 6`
`= 10000 + 1100 + 30 = 11130`
(iii) यहाँ
`(0.99)^(2) = (1-0.01)^(2) = (1)^(2) - 2 xx 1 xx 0.01 + (0.01)^(2)`
`= 1 - 0.02 + 0.0001 = 1.0001 - 0.02 = 0.9801`