
Since the form is indeterminant
\(=\cfrac00\)
Method 1: factorization

Since a3 + b3 = (a + b)(a2 + b2 - ab) & a2 - b2 = (a + b) (a - b)

= (-1)2 + (1)2 - (-1)
= 3
Method 2 : By L hospital rule:
Differentiating numerator and denominator separately:

= 3(-1)2
= 3