We need to find the limit for : \(\lim\limits_{\text x \to 1}\cfrac{\text x^3+1}{\text x+1} \)
As limit can’t be find out simply by putting x = –1 because it is taking indeterminate form(0/0) form, so we need to have a different approach.
Let, Z = \(\lim\limits_{\text x \to 1}\cfrac{\text x^3+1}{\text x+1} \)
Note: To solve the problems of limit similar to one in our question we use the formula mentioned below which can be derived using binomial theorem.
Formula to be used: \(\lim\limits_{\text x \to a}\cfrac{(\text x)^n-(a)^n}{\text x-a} \) = nan -1
As Z does matches exactly with the form as described above so we don’t need to do any manipulations–

Use the formula: \(\lim\limits_{\text x \to a}\cfrac{(\text x)^n-(a)^n}{\text x-a} \) = nan -1
∴ Z = 3(–1)3–1 = 3
Hence, \(\lim\limits_{\text x \to 1}\cfrac{\text x^3+1}{\text x+1} \) = 3