Question

Find the area of the rhombus, the length of whose diagonals are 30 cm and 16 cm. Also, find the perimeter of the rhombus.

Answer 1

Area of the rhombus = \(\frac{1}{2}\times d_1\times d_2\), where d₁ and d₂ are the lengths of the diagonals

= \(\frac{1}{2}\times 30\times 16\)

= 240 cm²

Side of thee rhombus = \(\frac{1}{2}\sqrt{d^2_1+d^2_2}\)

= \(\frac{1}{2}\sqrt{30^2+16^2}\)

= \(\frac{1}{2}\sqrt{1156}\)

= \(\frac{1}{2}\times 34\)

= 17 cm

Perimeter of the rhombus = 4a

= 4 x 17

= 68 cm