Here, sample space, `S = {1,2,3,4,5,6,7,8}`
So, `n(S) = 8`
As, pointing a number are equally likely outcomes, so, pointing a number will have a probability of `1/8`.
(i) From above, we can say that arrow pointing at number `8` will have a probability of `1/8`.
(ii)Odd numbers in given sample space, ` E_o= {1,3,5,7}`
So,`n(E_o) = 4`
Probability of arrow pointing at odd number, `P(E_o) = 4/8 = 1/2`
(iii)Number greater than 2,`E_g = {3,4,5,6,7,8}`
So,`n(E_g) = 6`
Probability of arrow pointing a number greater than 2, `P(E_g) = 6/8 = 3/4`
(iii)Number less than 9,`E_l = {1,2,3,4,5,6,7,8}`
So,`n(E_l) = 6`
Probability of arrow pointing a number less than 9, `P(E_l) = 8/8 = 1`