Question

From the top of a tower a stone is thrown up which reaches the ground in a time t₁. A second stone is thrown down with the same speed reaches the ground in time t₂. A third stone is released from rest from the same point which reaches ground in time t₃, then

(a) t₃ = \(\sqrt {t_1 + t_2}\)

(b) \(t^2_3\) = t₁t₂

(c) t₃ = \(\cfrac{t_1}{t_2}\)

(d) t₁ = t₂ t₃

Answer 1

Correct option: (b) \(t^2_3\) = t₁t₂ 

Let h be the height of tower and u be the speed of projection of stone

From Eq. (i), we get

From Eqs. (i) and (ii), we get