Question

Compressibility of water is `5xx10^(-10)m^(2)//N`. Find the decrease in volume of `100 mL` of water when subjected to a pressure of `15 MPa`.

Answer 1

The compressibility `K` is the reciprocal of the bulk moxulus.
`:/_V=-VK/_p`
`=-((100mL)95xx10^(-10)m^(2)//N)(15xx10^(6)N//m^(2))`
`=-0.75mL`
The decrease in volume is thus `0.75mL`.