Question

The derivative of `|x|` at x = 0
A. is 1
B. is `-1`
C. is 0
D. does nto exist

Answer 1

Correct Answer - D

Since `|x|={{:("x if x" ge 0),("-x if x" lt 0):}`
`therefore` R.H.D of |x| = 1 at x = 0
and L.H.D of |x| = -1 at x = 0
Now, R.H.D `ne` L.D.D at x = 0
Hence, the derivative of |x| at x = 0 does not exist.