Correct Answer - A
`98% H_(2)SO_(4)` by mass means 98 g `H_(2)SO_(4)` present in 100 g of the solution.
`"Volume of solution"=("Mass")/("Density")=(100)/(1.80)mL=(1)/(18)L`
Moles of solute `=(98)/(98)=1 mol` ltBRgt Molarity = 18M
Now `M_(1)V_(1)=M_(2)V_(2)`
`therefore10MxxV_(1)=1000mLxx0.1M`
Hence `V_(1)=5.55mL.`