Correct Answer - Option 3 : 125 l/s
Concept:
The rate of flow from Venturimeter is given as
\(Q = \;{C_d}\frac{{{A_1}{A_2}}}{{\sqrt {A_1^2 - A_2^2} }} \times \sqrt {2gh} \)
Where,
A1 and A2 are cross sectional area at inlet and throat section
h = differential manometer head
\(h = X\;\left( {\;\frac{{{\rho _{Hg}}}}{\rho } - 1} \right)\)
Where,
X = differential manometer reading
Calculation:
Given,
d1 = 30 cm ; d2 = 15 cm, Cd = 0.98, x = 20 cm
\({A_1} = \frac{\pi }{4}{\left( {0.3} \right)^2} = 0.07065\;{m^2}\)
\({A_2} = \frac{\pi }{4}{\left( {.15} \right)^2} = .01766\;{m^2}\)
\(h = 0.2 \times \left( {\frac{{13.6}}{1} - 1} \right) = 2.52\;m\)
\(Q = 0.98 \times \frac{{.07065\; \times .\;01766}}{{\sqrt {{{\left( {.07065} \right)}^2} - {{\left( {01766} \right)}^2}} }} \times \sqrt {2 \times 9.81 \times 2.52} \)
Q = 128 l/s
Q ≈ 125 l/s